Rotating Reference Frames

Few ideas in mechanics get tangled as often as centripetal and centrifugal. They sound like opposites, and in a sense they are. These two words often describe the same phenomenon, but from two different points of view.

  • Centripetal force is real, used from a point of view where an object is moving along a circular path. It points inward (toward the center of the circle) and holds the object along its circular path: tension in a string, gravity on a planet, friction on a cornering car. “Centripetal” is not a new kind of force — it is simply an adjective for the net inward force.
  • Centrifugal force is apparent, used from a point of view within a rotating frame of reference. From an outside point of view, nothing is actually pushing the object outward. The outward “force” you feel on a merry-go-round is what it takes to make Newton’s laws bookkeep correctly from inside a rotating frame. Alongside it lives a second apparent force, the Coriolis force.

The Inward Acceleration of Circular Motion

An object moving in a circle is always accelerating, even at constant speed, because its velocity keeps changing direction. That acceleration points toward the center with magnitude

acentripetal=v2r=rω2.a_{\text{centripetal}} = \frac{v^2}{r} = r\omega^2.

Change the radius or angular speed. Arrow lengths track their magnitudes: velocity stays tangent while acceleration points toward the center.

rvac
v = rω = 4.50m/sac = v²/r = rω² = 6.75m/s²

The word centripetal means “center-seeking”, i.e. the acceleration is directed toward the center of some circle. To produce this centripetal acceleration, some combination of forces with a net inward component is required, F=macentF = ma_{\text{cent}}. If these forces are suddenly removed, the object would fly off along a straight line.

Where do the centripetal and Coriolis terms come from?

Working in polar coordinates, the acceleration of a point splits into a radial part and a transverse part:

a=(r¨rθ˙2)r^+(rθ¨+2r˙θ˙)θ^.\vec a = \left(\ddot r - r\dot\theta^2\right)\hat{\mathbf r} + \left(r\ddot\theta + 2\dot r\dot\theta\right)\hat{\boldsymbol\theta}.

These terms are byproducts of choosing polar coordinates, not new physics. But two of them have names:

  • rθ˙2-r\dot\theta^2 is the centripetal term — the inward acceleration of circular motion.
  • 2r˙θ˙2\dot r\dot\theta is the Coriolis term — it appears only when the radius is changing (r˙0\dot r \neq 0) while also rotating.

Riding Inside the Rotating Frame

Everything above is the view of an outside, non-rotating observer, who needs only real forces. Now move inside the rotation. To keep using F=ma\vec F = m\vec a in a frame spinning at Ω\Omega, an observer must add two apparent (fictitious) accelerations:

acentrifugal=Ω2r(outward),aCoriolis=2Ω×vrel.\vec a_{\text{centrifugal}} = \Omega^2\,\vec r \quad(\text{outward}), \qquad \vec a_{\text{Coriolis}} = -2\,\vec\Omega\times\vec v_{\text{rel}}.

The centrifugal term is the outward push you feel; the Coriolis term deflects anything that moves within the frame. Neither corresponds to a real interaction — they are the price of describing the world from a turning point of view. From outside, a Formula 1 driver is being pulled inward through a tight left turn; from inside the car, it feels exactly like being thrown to the right.

The spaceship below makes this switch concrete. A ring-shaped ship rotates against a field of stars. Pick a frame, set a comfortable spin, and click Drop ball.

Rotating Spaceship Frame

Switch between the star (inertial) and ship (rotating) frames, then drop a ball to watch the centrifugal and Coriolis effects appear.

From the star frame, the ball simply travels in a straight line until it strikes the hull — no mysterious forces, just inertia. From the ship frame, the same motion looks strange: the ball curves as if pushed by two effects at once —

  • toward the floor, more strongly the farther out you are (centrifugal);
  • sideways, at a right angle to its velocity (Coriolis).

If you spent your whole life inside the ship with no window to the stars, you might never call these “apparent.” You would simply measure them — and, noticing that they depend on θ˙\dot\theta, deduce that you live inside a giant rotating circle. In that moment θ˙\dot\theta stops being the rate of change of some object’s angle and becomes a physical property of your reference frame itself.

That is the heart of the centripetal–centrifugal distinction: centripetal is the real inward force that bends a path into a circle, while centrifugal and Coriolis are the apparent forces you invent to explain that same motion from a frame that is itself turning.

Problem Solving

Centripetal Acceleration

Problem

A car moves at 12 m/s12\ \text{m/s} around a circular path of radius 6.0 m6.0\ \text{m}. Find the centripetal acceleration.

Solve

acent=v2r=1226.0=24 m/s2.a_{\text{cent}} = \frac{v^2}{r} = \frac{12^2}{6.0} = 24\ \text{m/s}^2.

The acceleration points inward, toward the center of the circular path.

Apparent Spin Gravity

Problem

A rotating frame has angular speed Ω=0.50 rad/s\Omega = 0.50\ \text{rad/s}. At radius 20 m20\ \text{m}, what centrifugal acceleration would an observer in the rotating frame assign?

Solve

acentrifugal=Ω2r=(0.50)2(20)=5.0 m/s2.a_{\text{centrifugal}} = \Omega^2 r = (0.50)^2(20) = 5.0\ \text{m/s}^2.

In the rotating frame this apparent acceleration points outward.

Rotating Frames Checkpoint

Question 1 of 3

From an inertial frame, what does centripetal force describe?

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